9[z-(2z+16)+7]=3(z+9)

Solution for 9[z-(2z+16)+7]=3(z+9) equation:

Simplifying
9[z + -1(2z + 16) + 7] = 3(z + 9)

Reorder the terms:
9[z + -1(16 + 2z) + 7] = 3(z + 9)
9[z + (16 * -1 + 2z * -1) + 7] = 3(z + 9)
9[z + (-16 + -2z) + 7] = 3(z + 9)

Reorder the terms:
9[-16 + 7 + z + -2z] = 3(z + 9)

Combine like terms: -16 + 7 = -9
9[-9 + z + -2z] = 3(z + 9)

Combine like terms: z + -2z = -1z
9[-9 + -1z] = 3(z + 9)
[-9 * 9 + -1z * 9] = 3(z + 9)
[-81 + -9z] = 3(z + 9)

Reorder the terms:
-81 + -9z = 3(9 + z)
-81 + -9z = (9 * 3 + z * 3)
-81 + -9z = (27 + 3z)

Solving
-81 + -9z = 27 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-81 + -9z + -3z = 27 + 3z + -3z

Combine like terms: -9z + -3z = -12z
-81 + -12z = 27 + 3z + -3z

Combine like terms: 3z + -3z = 0
-81 + -12z = 27 + 0
-81 + -12z = 27

Add '81' to each side of the equation.
-81 + 81 + -12z = 27 + 81

Combine like terms: -81 + 81 = 0
0 + -12z = 27 + 81
-12z = 27 + 81

Combine like terms: 27 + 81 = 108
-12z = 108

Divide each side by '-12'.
z = -9

Simplifying
z = -9